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Mathematics 12 Online
OpenStudy (anonymous):

What is the derivative of this? I think it involves partial derivatives but I'm not sure? (see image)

OpenStudy (anonymous):

OpenStudy (anonymous):

Would it be p(q)-C(q) ?

OpenStudy (anonymous):

Or would it be 0??? Would you hold p(q) and -C(q) constant and treat them as constants so their deriv. would be 0 cancelling out the derivative of q =1?

jimthompson5910 (jim_thompson5910):

I don't think you're taking partial derivatives

jimthompson5910 (jim_thompson5910):

you're just deriving with respect to q so deriving p(q) with respect to q gives you p'(q) deriving p(q)*q with respect to q gives: p'(q)*q + p(q)*1 ---> p'(q)*q+p(q) I'm using the product rule

jimthompson5910 (jim_thompson5910):

deriving C(q) with respect to q gives C'(q)

jimthompson5910 (jim_thompson5910):

hopefully this is making sense

OpenStudy (anonymous):

Great sense of what it means to take the derivative of a function with respect to a variable

OpenStudy (anonymous):

Oh! Thank you I understand. I was over thinking this and trying to do something else completely.

jimthompson5910 (jim_thompson5910):

you're welcome

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