Question

A package contains 18 candy canes, 13 of which are cracked. If 4 are selected, find the probability of getting exactly four cracked candy canes.

Answer 1

Hint:

The probability of selecting one cracked candy cane is \(\dfrac{13}{18}\)

The probability of selecting a second cracked candy cane is \(\dfrac{13 - 1}{18 - 1}\)

The probability of selecting a third cracked candy cane is \(\dfrac{13 - 2}{18 - 2}\)

Notice a pattern?

After finding the probability of selecting the fourth cracked candy cane, multiply all four probabilities together to find the probability of selecting four cracked candy canes