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Mathematics 21 Online
OpenStudy (dannyrod2000):

Shifting functions vertically and horizontally

OpenStudy (dannyrod2000):

OpenStudy (dannyrod2000):

@jtryon

OpenStudy (anonymous):

you are shifting to the left 3 units

OpenStudy (dannyrod2000):

yes so it will be (x+3)^2?

OpenStudy (dannyrod2000):

i got it wrong @jtryon

OpenStudy (anonymous):

what did you put?

OpenStudy (dannyrod2000):

i asked you (x+3)^2 and you just left so i just put this @jtryon

OpenStudy (anonymous):

that should be correct... is that the right graph?

OpenStudy (dannyrod2000):

yup for sure

OpenStudy (anonymous):

oh, wait... I see something

OpenStudy (dannyrod2000):

i got (x+2)^2+1

OpenStudy (anonymous):

yes, it is shifted vertically by 1

OpenStudy (dannyrod2000):

it is i mean

OpenStudy (anonymous):

so it is not only shifted to the left but also up

OpenStudy (anonymous):

I was looking at your old graph

OpenStudy (dannyrod2000):

which one?

OpenStudy (anonymous):

the one that was just shifted to the left

OpenStudy (anonymous):

I didn't see that it was also shifted up

OpenStudy (dannyrod2000):

o

OpenStudy (anonymous):

do you have any more?

OpenStudy (dannyrod2000):

yea

OpenStudy (dannyrod2000):

ill put on please wait

OpenStudy (dannyrod2000):

ill tell you when it is ready

OpenStudy (solomonzelman):

V units left and C unit up. This makes \[g(x)=x^2\]into\[g(x)=(x+V)^2+C\]

OpenStudy (dannyrod2000):

@jtryon

OpenStudy (anonymous):

so before I give you answer, do you see the two shifts, one horizontally and one vertically?

OpenStudy (dannyrod2000):

yes @jtryon

OpenStudy (anonymous):

which way is it shifting?

OpenStudy (dannyrod2000):

up four units and right three units

OpenStudy (anonymous):

ok, that is great and how do you write that?

OpenStudy (dannyrod2000):

(x+4)^2-3?

OpenStudy (anonymous):

not quite

OpenStudy (anonymous):

so it would be (x-3)^2 + 4

OpenStudy (anonymous):

horizontal shift happens inside the () and on the outside is the vertical shift

OpenStudy (anonymous):

does that make sense now?

OpenStudy (dannyrod2000):

so you have to put the right three units in parenthesis

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

it is either going to shift left or right and/or up and down

OpenStudy (dannyrod2000):

shouldn't you have to put it outside the parenthesis?

OpenStudy (anonymous):

I am actually doing the same kind of problems in class :)

OpenStudy (dannyrod2000):

o

OpenStudy (anonymous):

if it is outside the parenthesis, that is a vertical shift

OpenStudy (anonymous):

that takes care of the up and down shifting

OpenStudy (dannyrod2000):

i got an other one can i show you?

OpenStudy (dannyrod2000):

@jtryon

OpenStudy (dannyrod2000):

@jtryon

OpenStudy (dannyrod2000):

@jtryon

OpenStudy (anonymous):

ok, I am looking now

OpenStudy (anonymous):

what do you see from this one?

OpenStudy (dannyrod2000):

it is shifted down three units and left two units

OpenStudy (anonymous):

OK, how do we write that one?

OpenStudy (dannyrod2000):

(x+2)^2-3?

OpenStudy (anonymous):

you got it :)

OpenStudy (anonymous):

I think you have got the hang of this

OpenStudy (dannyrod2000):

you sure because i can't miss no more in my quiz if i get it wrong i have to do a quiz again

OpenStudy (anonymous):

we can do a couple more

OpenStudy (dannyrod2000):

is it correct then?

OpenStudy (anonymous):

this one is correct

OpenStudy (dannyrod2000):

the

OpenStudy (dannyrod2000):

(x+2)^2-3?

OpenStudy (anonymous):

yes

OpenStudy (dannyrod2000):

@jtryon

OpenStudy (dannyrod2000):

@SolomonZelman

OpenStudy (anonymous):

what is happening in the function?

OpenStudy (dannyrod2000):

it is 1 left and 4 right i think

OpenStudy (anonymous):

no try again

OpenStudy (dannyrod2000):

this one is tricky

OpenStudy (anonymous):

think about the horizontal shift first

OpenStudy (dannyrod2000):

3? @jtryon

OpenStudy (anonymous):

no, count the shift

OpenStudy (dannyrod2000):

4?

OpenStudy (anonymous):

there you go

OpenStudy (anonymous):

and the vertical one?

OpenStudy (dannyrod2000):

ok and the verticle is 1?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so what is the answer?

OpenStudy (dannyrod2000):

i have to go would you still be on in about 2 hours?

OpenStudy (anonymous):

I should still be here

OpenStudy (dannyrod2000):

(x-4)^2+1 and ok great

OpenStudy (anonymous):

tag my name and I will see it

OpenStudy (anonymous):

put an @ sign in front of my name

OpenStudy (dannyrod2000):

is (x-4)^2+1 correct? @jtryon

OpenStudy (anonymous):

correct

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