Question

evaluate sec 10pi/3

Answer 1

sec(10π/3) = sec(10 × 180 /3) = sec(600)=1/cos(600)

Can you solve for cos(600) knowing that

cos(600)=cos(570+30)=cos(570)cos(30) - sin(570)sin(30)


\(\large\color{blue}{ \bf Cos(570) }\) = cos(570 - 360) = cos(210)= -cos(210-180) = \(\large\color{blue}{ \bf -cos(30) }\) =-√(3) / 2

sin(570)= sin( 570°-360°) = sin 210°
sin 210° = sin(180°+30°) = -sin 30° = -1/2

Answer 2

hence, you are going to get,

\(\large\color{blue}{ \bf Cos(600) =cos(570-30)=(\frac{\sqrt{3} }{2})^2 - (-\frac{1 }{2})\frac{1 }{2} }\)

Answer 3

\(\large\color{blue}{ \bf Cos(600) =cos(570-30)=(\frac{\sqrt{3} }{2})^2 +(\frac{1 }{2})^2 }\) take it from here....

Answer 4

don't forget though, that it is 1/cos(600) not just cos(600)

Answer 5

so the end is what?

Answer 6

do i squared them and take that answer?

Answer 7

\(\LARGE\color{blue}{ \bf (\frac{\sqrt{3} }{2} ) ^2+(\frac{1 }{2} ) ^2}\)


\(\LARGE\color{blue}{ \bf \frac{3 }{4} +\frac{1 }{4} }\)


\(\LARGE\color{blue}{ \bf 1 }\)