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Mathematics 15 Online
OpenStudy (anonymous):

check please True or false: As long as its argument is restricted to [0,2pi] the polar form of a complex number is unique.

OpenStudy (anonymous):

i think it's false but i want to make sure that im right

jimthompson5910 (jim_thompson5910):

why do you think it's false?

OpenStudy (anonymous):

because the argument is not unique for complex numbers

jimthompson5910 (jim_thompson5910):

here is an xy axis |dw:1400463275652:dw|

jimthompson5910 (jim_thompson5910):

let's say we plotted the point (x,y) = (0,1) |dw:1400463309504:dw|

jimthompson5910 (jim_thompson5910):

what is the polar form of that number?

jimthompson5910 (jim_thompson5910):

of that point I mean

OpenStudy (anonymous):

is it (cos(pi/2) + sin(pi/2)) ?

jimthompson5910 (jim_thompson5910):

what is r? what is theta?

OpenStudy (anonymous):

r is 0 and theta is pi/2?

jimthompson5910 (jim_thompson5910):

r is 1 actually

jimthompson5910 (jim_thompson5910):

you start at the origin, or the pole, and you go 1 unit away from it to land on (0,1)

jimthompson5910 (jim_thompson5910):

the angle is pi/2, or 90 degrees

OpenStudy (anonymous):

oh okay

jimthompson5910 (jim_thompson5910):

but this isn't the only way to represent the point (0,1) we could have (r,theta) = (-1, 270 degrees) so you rotate 270 degrees |dw:1400463730873:dw|

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