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A particle moving in a straight line has an acceleration given by a(t)=2t . The initial velocity of the particle is 2 cm/sec. How far does the particle move between t =1and t = 2 seconds?
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s=ut+(1/2)at^2
could you explain that a bit more, im having a hard time understanding
In the above expression, u is the starting velocity; t is time; and a is the acceleration. In your problem it's given that u=2cm/s and a=2t. Does that help?
s=2t+(1/2)*2t*t^2 s=2t+t^3
put t=1 nd t=2 then subtract s
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if u feel more difficulty plz ask
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