Question

Which one is not a valid value of x?
√x^2–10x+25+12 √x=15 √x ?
how do you solve this? here are the answers
a)17.57
b)14.25
c)1.757
d)1.425
i need help! :(

Answer 1

Just plug in the options you have for x.

Answer 2

Then get rid of which one is not valid.

Answer 3

i got 17.57?

Answer 4

im not sure i dont want to get it wrong :(((((

Answer 5

let me see if i can read it

Answer 6

\[\sqrt{x^2-10x+25}+12\sqrt{x}=15\sqrt{x}\]?

Answer 7

its weird!

Answer 8

YEA THATS HOW IT LOOKS LIKE :D

Answer 9

<(*^*)>

Answer 10

ok lets see what we can do

Answer 11

\[\sqrt{x^2-10x+25}+12\sqrt{x}=15\sqrt{x}\]
\[\sqrt{(x-5)^2}+12\sqrt{x}=15\sqrt{x}\]
\[x-5+12x\sqrt{x}=15\sqrt{x}\] might be a good start

Answer 12

ok so far?

Answer 13

then maybe
\[x-5=3\sqrt{x}\] after subtracting
now we can solve without too much trouble

Answer 14

square both sides and get
\[x^2-10x+25=9x\] then a quadratic equation
\[x^2-19+x+25=0\]

Answer 15

no, make that
\[x^2-19x+25=0\]

Answer 16

i get the following answers using the quadratic formula
\[1.42,17.58\] rounded
those are the only two

Answer 17

I chose 17.57 but i got wrong its okay i still love you :'(