Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Identify the equation of the ellipse. (attached photo)

OpenStudy (anonymous):

OpenStudy (anonymous):

the one that looks like \[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\]

OpenStudy (anonymous):

oh damn you have to come up with the equation, don't you?

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

i can't see it that well can you tell what the center is from the picture?

OpenStudy (anonymous):

looks like maybe \((2,-3)\) ?

OpenStudy (anonymous):

Yes it's 2, -3

OpenStudy (anonymous):

i wish i could be of more useful to people ;p

OpenStudy (anonymous):

ok then we can do it the distance between the very top and \((2,-3)\) is \(5\) units and the the distance between \((2,3)\) and the side is \(3\) units it looks like to me

OpenStudy (anonymous):

@RostikLegends follow along and you will learn how to find the equation of an ellipse no one likes these problems, you could help others

OpenStudy (anonymous):

since it looks like the one on the right, not the one on the left, the bigger number goes under the \(y^2\) term |dw:1400467839939:dw|

OpenStudy (anonymous):

put \[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\] with \((h=2,k=-3,a=3,b=5\)

OpenStudy (anonymous):

\[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\] \[\frac{(x-2)^2}{9}+\frac{(y+3)^2}{25}=1\] should do it

OpenStudy (anonymous):

Thank you so much! I get how you did that!!

OpenStudy (anonymous):

great! wasn't really that hard once you know what to do

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!