Question

Write an equation of a line that is perpendicular to y=-5x+2 and passes through (10,8)

Answer 1

equation of a line perpendicular to y=mx+c and passing through x1,y1
is given by
y-y1= (-1/m) *(x-x1)

Answer 2

for y=-5x +2 m=-5

Answer 3

y = (x/5)+6

Tell me if you need the steps.

Answer 4

I would really appreciate the steps @Blank.

Answer 5

Just a second...

Answer 6

y=-5x+2
(10,8)

To find the slope and y intercept, use the y=mx+b formula where m=slope and b is the y intercept.
y=mx+b

Using the y=mx+b formula, m=-5.
m=-5

The equation of a perpendicular line to y=-5x+2 must have a slope that is the negative reciprocal of the original slope.
mperp=-(1)/(-5)

The negative reciprocal of <Z>I<z> is 0.
mperp=(1)/(5)

Find the equation of the perpendicular line using the point-slope formula.
(10,8)
m=(1)/(5)

Find the value of b using the formula for the equation of a line.
y=mx+b

Substitute the value of m into the equation.
y=(1/5)*x+b

Substitute the value of x into the equation.
y=(1/5)*(10)+b

Substitute the value of y into the equation.
(8)=(1/5)*(10)+b

Since b is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
(1/5)*(10)+b=(8)

Multiply ((1)/(5)) by (10) to get ((1)/(5))(10).
((1)/(5))(10)+b=8

Multiply (1)/(5) by 10 to get 2.
2+b=8

Since 2 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2 from both sides.
b=-2+8

Add 8 to -2 to get 6.
b=6

Now that the values of m(slope) and b(y-intercept) are known, substitute them into y=mx+b to find the equation of the line.
y=(x)/(5)+6


Hope this helps. :)

Answer 7

Thank you!! @Blank 

Answer 8

ǝɯoɔlǝʍ ǝɹ,noʎ :)