In the absence of friction, gravity, and all other external forces, what kind of speed will an object display if it travels from the bottom to the top of an inclined plane?
Answers choices A) constant speed B) increasing speed C) decreasing speed D) speed increases and then decreases E) speed decreases and then increases
its answer is A) constant speed
What about this one A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds of its travel. What is its average speed during the time from t = 5 seconds to t = 10 seconds? 2 meters/second 3 meters/second 4 meters/second 5 meters/second 6 meters/second
If the only force is the force propelling the object up the ramp, then it's motion will be described by an acceleration given by:\[a=\frac{ F }{ m }\]
Note what the object experiences depends on whether it is given speed via an impulse force--and force over a very small amount of time--or whether it's give a constant force over the move up the ramp. Without such a force, the object would not move up the ramp.
@PsiSquared there is no any external force.
If there is no external force, then the object cannot move up the ramp and thus has a constant velocity of zero, unless the object was already in motion.
Yup apply the Newton's first law of motion.
So what's the answer
2nd's answer is 4 meter per second.
Thanks
Which branch of science involves the study of matter and energy?
Yep, 4m/s over the second 5 sec.
Physics.
Answer of first question is A). constant velocity. and the answer of 2nd question is 4 meter per second. and the Physics deals with matter and energy.
Is it physics
YEs.
Galileo’s pendulum theory stated that the time taken to swing through one complete cycle of a pendulum depends on what? the mass tied to it the amplitude of the swing the length of the string the velocity of the pendulum the volume of the mass tied
The length of the string
Hey Mr. Malik are you going to able to help me with all my questions please
The period of a pendulum is given by:\[T=2\pi \sqrt{\frac{ l }{ g }}\]where T is period; l is the length of the pendulum; and g is the acceleration of gravity.
sure..
Which is the correct product of the significant figures 3.278 and 4.23? 14 13.9 13.86 13.865 13.86594
13.9
13.9
Of the two figures you carry the number of significant digits equal to the smaller of the numbers given. This is to say if one number has 5 significant digits and the other 2, you only carry 2 significant digits.
Thanks
How many meters is 32 kilometers? 3.2 × 10-5 meters 3.2 × 10-4 meters 3.2 × 103 meters 3.2 × 104 meters 3.2 × 105 meters
That is the 4th one...
Yes my parents are but I am in USA TX
Sir Its 3.2 * 10 ^ 4
Good..
\[3.2 \times 10^{4}\]
Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous planet varies linearly with the height of the atmosphere as measured from the top of a visible boundary layer. The instruments on board can withstand a temperature of 601 K. At what altitude will the probe's instruments fail? 50 kilometers 80 kilometers 83 kilometers 100 kilometers 111 kilometers
@PsiSquared
Hardest one
I hate physics that's why asking you guys!
Did you guys find the answer
That is 83 km
I guess you don't want to help
The density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as measured from the planet's surface). What type of relationship exists between the altitude and the atmospheric density, and what would the atmospheric density be at an altitude of 1,291 kilometers? inverse plot, 0.45 kilograms/meter3 inverse plot, 0.51 kilograms/meter3 quadratic plot, 1.05 kilograms/meter3 inverse plot, 1.23 kilograms/meter3 inverse plot, 0.95 kilograms/meter3
The temperature is a linear function of depth in the atmosphere. The slope of that function is:\[\frac{ 567K-147.54K }{78.11km-18.4km }=7.02K/km\]Therefore the depth at which the temp is 83.5km or approximately 83km.
Note that you have to give us time to help you. Also note that this isn't a place where answers are supposed to be just handed out. Some learning has to happen. Moderators will step in and stop things if only answers are given out.
Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous planet varies linearly with the height of the atmosphere as measured from the top of a visible boundary layer. The instruments on board can withstand a temperature of 601 K. At what altitude will the probe's instruments fail? 50 kilometers 80 kilometers 83 kilometers 100 kilometers 111 kilometers
The density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as measured from the planet's surface). What type of relationship exists between the altitude and the atmospheric density, and what would the atmospheric density be at an altitude of 1,291 kilometers? inverse plot, 0.45 kilograms/meter3 inverse plot, 0.51 kilograms/meter3 quadratic plot, 1.05 kilograms/meter3 inverse plot, 1.23 kilograms/meter3 inverse plot, 0.95 kilograms/meter3
These are some hard questions.
w8 some mistake
:)
With the question there is a mistake are you saying
Malik I don't know what's wrong I just have you guys what's on my paper
Actually I am really sorry guys.
Hello Answer my Question Please
0.51
Thanks Malik Given this graph plotting velocity versus time, estimate the acceleration of object A at points X and Y respectively. 0 meters/second2 and -1 meter/second2 0 meters/second2 and +1 meter/second2 5 meters/second2 and -2 meters/second2 9 meters/second2 and -1 meter/second2 0 meters/second2 and +3 meters/second2
I am having trouble with the graph questions only );
InshaAllah Malik can you help me
5 meter per second suqare and -2 meter per second suqare.
Sir @PsiSquared check the last one.. i'm a bit confused,..
A rocket initially at rest accelerates at a rate of 99.0 meters/second2. Calculate the distance covered by the rocket if it attains a final velocity of 445 meters/second after 4.50 seconds. 2.50 × 102 meters 1.00 × 103 meters 5.05 × 102 meters 2.00 × 103 meters 1.00 × 102 meters
:o
2nd one is correct.
1.00 × 10^3 meters
A van traveling down a slope with a uniform acceleration of 2.15 meters/second2 attains a speed of 20.00 meters/second after 7.00 seconds. What is the initial velocity of the van? 0.00 meters/second 3.65 meters/second 4.95 meters/second 35.05 meters/second 120.75 meters/second
Malik can you help me fast this is due in 3 hours
Hello
Going back to the first question: In the absence of gravity it does not make sense to refer to the 'bottom' and 'top', or to an inclined plane (it is only inclined to the 'horizontal' which is defined by the direction of gravity)
Which statement correctly defines displacement? the maximum distance between the starting point and the ending point of a motion the shortest distance between the starting point and the ending point of a motion the maximum distance between the starting point and the ending point of a motion, measured in the direction of motion the distance vector between the starting point and the ending point of a motion the distance vector between the ending point and the starting point
Answer of 2nd last question is.... 4.95 meter per second
Answer of the above question is.... The shortest distance between the starting point and ending point of a motion.
Join our real-time social learning platform and learn together with your friends!