Find the area bounded by the curves x = 5 - y^2 and x - 2y = -5.
first, find out where two curves intersect so set them equal to each other and solve for x.
or you could solve for y and then find out the x value by plugging in.
okay I graphed it. I found where the curves intersect
(1,-2) and (5,0)
k now i plug that into an integral
Yeah. Remember area = top curve - bottom curve your bounds are from x = 1 to x = 5
(12)-(12-8y)
does that look right?
nope
k let me try again
x = 5-y^2 x = 2y - 5 2y - 5 is the top curve 5-y^2 is the bottom curve change it to a function of y and then integrate it with respect to x
so I have to get y on one side of the equation. and the x's on the other and then integrate
yeah just change it
5 - x = y^2 sqrt(5-x) = y x + 5 = 2y (x+5)/2 = y so the integral would be: \[\int\limits_{1}^{5} (\frac{ x+5 }{ 2 } - \sqrt{5-x}) dx\]
I keep getting 10.66 but that is not the right answer.
hm, maybe integrate it with respect to y?
okay I will try that
the bounds will be different,
What will I change the bounds to?
will it be -2 to 0
the y coordinates
yeah
2y - 5 - (5-y^2) dy integrate that from -2 to 0
Join our real-time social learning platform and learn together with your friends!