shifting functions vertically and horizontally
@jtryon
might be D
When you shift a function to the right by 'a' units, you subtract 'a' from every variable 'x' in the function. That is, the function f(x) becomes f(x - a). Here H(x) becomes H(x - 5) when you shift it five units to the right. Similarly when you shift a function vertically, a constant value is added/subtract from the function itself. So shifting H(x - 5) 2 units down will give you a new function H(x - 5) - 2
Given H(x) = 4x^2 - 16, we get H(x - 5) - 2 = 4(x - 5)^2 - 16 - 2 = 4(x - 5)^2 - 18 D seems the right answer
yes D when its shifted 5 units to the right then h(x)=h(x-5) so h(x)=4(x-5)^2-16 now 2 uints down so h(x)=4(x-5)^2-16-2=4(x-5)^2-18
thanks @sidsiddhartha and @navk and @matricked
yw
:)
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