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Mathematics 20 Online
OpenStudy (anonymous):

proof of derangement without using recurrence?

OpenStudy (wolf1728):

You have a question about derangements? I know (for example) that the number 123 has 2 derangements.

OpenStudy (wolf1728):

for example the 2 derangements of 123 are 231 and 312

OpenStudy (anonymous):

i am looking for a proof of derangement formula D(n)=n!(1-1/1!+1/2!..)so on but without using recurrence

OpenStudy (wolf1728):

The reason I am curious is that I wrote a derangement calculator just about a month ago: http://www.1728.org/derange.htm

OpenStudy (wolf1728):

I am searching for a proof of the derangement formula (which I assume you have done) without using recurrence of course. At the moment I have found the "Inclusion–exclusion principle" article in Wikipedia. http://en.wikipedia.org/wiki/Inclusion%E2%80%93exclusion_principle#Counting_derangements If you have already researched this please let me know.

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