Circle P is defined by the equation (x-4)^2+(y+3)^2 =49. Which of the following shows the location of the center of circle P and the radius of this circle?
standard form of the eq of a circle centre (a,b) radius "r" (x-a)^2 + (y-b)^2 = r^2
you should be able to work it out from here
@alekos beat me to it - just work from there but be careful of the signs... (+/-)
is it G then? i was confused between G and I
I'm not going to confirm your answer Look at the formula = (a,b) is the centre where (x-a) and (x-b) are in the formula. Check the signs...
But the final answer 7 or 49 confuses me
I'm not going to confirm your answer Look at the formula: (a,b) is the centre where (x-a) and (x-b) are in the formula. Check the signs... The final part of the equation says "=r^2" i.e. radius squared
kay its G then my confusion is over
!!!! CHECK YOUR SIGNS
then F since 4 must be positive and for -3 too -s equal addition
this is equation of a circle right?
the general equation has (x-a) : your equation has (x-4) so what is a? the general equation has (y-b) : your equation has (y+3) so what is b? the general equation has r^2 : your equation has 49 so what is r?
a is 4 and b is -3 ....and r^2 is 7^2 unless im getting confused by the equation mentioned at the top showing 49
you are correct - but what is confusing? 49 = 7^2
becuz for some reason i didnt know if i should pick 7^2 or 49 but i understood now
this is equation of a circle right?
The question (and @alekos ) tell you that it is a circle
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