Question

1 hemoglobin molecule contains 4 Ferum atoms.If 1g of hemoglobin contains 0.0341g of Ferum, calculate the relative molecular mass of hemoglobin.... PLS HELP!!!!!

Answer 1

make a ratio with what you know:

\(\dfrac{1~g~Hb}{0.0341~g~Fe}=\dfrac{M_{Hb}}{4*M_{Fe}}\)

the molar mass of Fe is 55.845 g/mol

\(\dfrac{1~g~Hb}{0.0341~g~Fe}=\dfrac{M_{Hb}}{4*55.845 ~g/mol}\)


\(M_{Hb}=\dfrac{1~g~Hb*[4*55.845 ~g/mol]}{0.0341~g~Fe}=6550.73~g/mol\)

Answer 2

Although, i think the mass of Fe the question should be 0.00341 g, because otherwise the final answer (above) is incorrect by an order of magnitude.