Question

PLEASE!!!!!
Solve the equation on the interval [0, 2π).

sec X/2 = cos X/2?

Answer 1

sec(x) is the inverse of cos(x)

Answer 2

so you can put 1/cos(x/2) in place of sec(x/2) in the equation

Answer 3

\[\sec(x/2)=\cos(x/2)~~~->~~\frac{1}{\cos(x/2)}=\frac{\cos(x/2)}{1}~~->~~\cos(x/2)=1\]can you take it from here?

Answer 4

IS IT (0)?

Answer 5

No you need to solve the equation cos^2(x/2) = 1

Answer 6

\[\pi/4,5\pi/4?\]

Answer 7

Yes it is pi/4 and 3pi/4

Answer 8

cos^2(x/2) = 1 is same as

cos(x/2) = ±1 this plus minus I left out, because 1/-1=-1/1, just like 1/1=1/1

Answer 9

SO IM RIHT OR NOT/

Answer 10

Your answer is half right pi/4 is right but how did you get 5pi/4 did you mean 3pi/4 ?

Answer 11

IT WASNT NONE OF MY CHOICES I GOT 3PI/4 BUT IT WASNT IN MY CHOICES