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OpenStudy (anonymous):
The molar mass CO2 is 44.01 g/mol. How many moles of LiOH are needed to react completely with 25.5 g of CO2?
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OpenStudy (chmvijay):
|dw:1400514039996:dw| LiOH molar mass =24g/mole 44.01 g of CO2 requires = 48 gram of LiOH from the above equation 25.5 g of CO2 = 48 *25.5 / 44.01 = X grams of LiOH moles = X grams of LiOH /molar mass of LiOH = ........... moles
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