Question

can someone please help me with this? picture posted below!!

Answer 1

"Let it go, let it go"

Answer 2

@hannah minx

Answer 3

NOPE.

Answer 4

ok... so looking at the periods

g(x) has a period of 2pi

so

f(x) has a period of pi

then

g(x) = asin(x)

f(x) = asin(2x)

if

\[f(\frac{\pi}{4}) = 4....then... 4 = asin(2\times \frac{\pi}{4})\]

so for f(x) a = 4

so \[f(x) = 4\sin(2x)\]

f(x) has an amplitude of 4

so g(x) has an amplitude of 2

so then

g(x) = 2sin(x)

thats my best guess

Answer 5

ook.. so g(x) = 2sin(x) would be my answer?

Answer 6

could you help me with one more?

Answer 7

@campbell_st

Answer 8

ok..well what is the centre of the curve... to find it

(12 + 52)/2 =

Answer 9

well to find the amplitude you need to 1st find the centre of the curve

(12 + 52)/2 =

Answer 10

its 32

Answer 11

then what?

Answer 12

@campbell_st

Answer 13

the amplitude is 20.... (52 -12)/2 = 20

so the equation is

\[y = 20\cos(bx) + 32\]

just from the period...