A truck undergoes a constant acceleration of 2.0 meters/second2 on a highway that slopes upward at an angle of 30.0° to the horizontal. What is the magnitude of the horizontal component of the acceleration?
1.0 meters/second2
1.2 meters/second2
1.7 meters/second2
2.0 meters/second2

Question

anonymous · Answer

To find the horizontal component of the acceleration use pythagoras theorem. Where the resultant acceleration (2.0m/s2) is the hypotenuse and the horizontal component is the adjacent. Giving us the equation :  

$$\cos \theta = \frac{ adjacent }{ hypotenuse }$$

then : 

$$Adjacent = hypotenuse \cos \theta $$

Where $$\theta $$ is equal to the angle = 90-30= 60

So, multiply the resultant acceleration by $$cos\theta $$ 

giving you 1m/s2

anonymous · Answer

What is the period of a satellite in a circular orbit just above the surface of the Moon? The Moon’s mass is 7.36 × 1022 kilograms and its radius is 
1.738 × 106 meters.

1.94 × 104 seconds
1.30 × 104 seconds
6.50 × 103 seconds
3.24 × 103 seconds
1.62 × 103 seconds