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which expression below is equivalent to 4i(12-7i) a)-28+48i b)28+48i c)48+28i d)-48=28i
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When you distribute 4i(12-7i), what do you get?
48i-28i^2?
what is i^2 equal to
i+i? lol idk
i by defintion is equal to sqrt(-1) in other words, \[\Large i = \sqrt{-1}\]
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oh wait its 1
so square both sides to get \[\Large i = \sqrt{-1}\] \[\Large i^2 = (\sqrt{-1})^2\] \[\Large i^2 = -1\]
so the answer is c?
Since \[\Large i^2 = -1\] we go from 48i-28i^2 to 48i-28(-1)
now simplify 48i-28(-1)
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oh okay so its b?
good
thanks a bunch!!!
you're welcome
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