If sin Θ = 3/5 and tan Θ > 0, what is the value of cos Θ?
\(\Large\rm \sin\theta\) is positive. \(\Large\rm \tan\theta\) is positive. So using that information, what `quadrant` is our angle theta in?
Quadrant 1?
hello?
Mmm good! So that let's us know that \(\Large\rm \cos\theta\) will be positive also.
|dw:1400546323951:dw|If we draw a triangle in the first quadrant
We can use the sine information to label the sides.
\[\Large\rm \sin \theta=\frac{opposite}{hypotenuse}=\frac{3}{5}\]
How does that help for the Cosine?
|dw:1400547432272:dw|You can find the missing side of the triangle by using the `Pythagorean Theorem`. Then you can easily find cosine by using your relationship,\[\Large\rm \cos \theta=\frac{adjacent}{hypotenuse}\]
Wait, whats the Adjacent? That's the last part I dont get
|dw:1400548136962:dw|
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