Question

Simplify.

http://static.k12.com/calms_media/media/241000_241500/241183/1/12fd67bb8b18acbc51bc9ca5926a2354d61e4024/02_16_UT_12_b.gif

@iambatman @satellite73

I also have about 12 questions, I really need someone to check after this one. Can you guys help!!??!?!

Answer 1

A. http://static.k12.com/calms_media/media/241000_241500/241187/1/58fff9c2bf4aca814bb894b8a57e6a48fa756f0a/02_16_UT_12d.gif

B. http://static.k12.com/calms_media/media/241000_241500/241185/1/32e15ec0c6019a00e589825b426af7e3714c7ca9/02_16_UT_12b.gif

C. http://static.k12.com/calms_media/media/241000_241500/241186/1/65c1cf457a8df473fc644ab73eb9389f1ab4c86d/02_16_UT_12c.gif

D. http://static.k12.com/calms_media/media/241000_241500/241184/1/59fee5135e098f6f97ca8469afcc1378c50fa2ef/02_16_UT_12a.gif

Answer 2

You can view the problem \[\sqrt[3]{x^{7}}\]
as \[(x ^{7})^{1/3}\]

Answer 3

And from there it may be easier to simplify further

Answer 4

I got x^(2) * 3sqrt(x)

Answer is B for first one. :)

Answer 5

you can think of it this way:
3 goes in to 7 two times
out comes \(x^2\)
the remainder is 1, in stays \(x^1\)

Answer 6

ok...

Answer 7

that makes
\[\large \sqrt[3]{x^7}=x^2\sqrt[3]{x}\]

Answer 8

i guess all those links are your answer choices, see of one agrees with the answer written above

Answer 9

The method performed by @satellite73 may be the preferred method

Answer 10

@Johnbc they are really identical, except that you don't really need exponential notation, but it come down to the same thing
like writing
\[\frac{7}{3}\] as a mixed number

Answer 11

@satellite73 B? :)

Answer 12

if B is
\[\large x^2\sqrt[3]{x}\] then yes

Answer 13

yes, B

Answer 14

Yep. :):):)