Put the equation in quadratic formula form.
x^2+3x+7=9

Question

Put the equation in quadratic formula form.
x^2+3x+7=9

anonymous · Answer

$$\huge  x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$$

campbell_st · Answer

well set the equation to zero by subtracting 9 from both sides

and you get 

$$x^2 + 3x - 2 = 0$$

the formula is 

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

for your question a = 1, b = 3 and c = -2

just substitute and calculate away.

hope it helps

anonymous · Answer

The standard form of a quadratic equation looks like

$$ax^2+bx+c = 0$$

a, b, and c are known values here as campbell explained, and of coarse x is the unknown.

shamim · Answer

quadratic equation is as
ax^2+bx+c=0

anonymous · Answer

-3$$\frac{ -3\pm \sqrt{9+6}}{ 2 }$$