Question

Put the equation in quadratic formula form.
x^2+3x+7=9

Answer 1

\[\huge x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 2

well set the equation to zero by subtracting 9 from both sides

and you get

\[x^2 + 3x - 2 = 0\]

the formula is

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

for your question a = 1, b = 3 and c = -2

just substitute and calculate away.

hope it helps

Answer 3

The standard form of a quadratic equation looks like

\[ax^2+bx+c = 0\]

a, b, and c are known values here as campbell explained, and of coarse x is the unknown.

Answer 4

quadratic equation is as
ax^2+bx+c=0

Answer 5

-3\[\frac{ -3\pm \sqrt{9+6}}{ 2 }\]