The larger the pH scale value, the: higher the concentration of H3O+ ions lower the concentration of H3O+ ions lower the concentration of OH− ions more acidic the solution (I would say the more acidic the solution am I correct?)
Hint: Higher concentration of H+ means lower pH and lower pH means it is more acidic.
High Ph is basic
It's a low concentration of hydronium ions. Just remember, high Ph = low hydronium; low ph = high hydronium.
(hydronium = h30+)
ohhh ok so if thats true then it's C?
No, it's B.
oh my bad!
OH- would be high on a high ph value.
I understand now thank you for your help again!
:D
Do you think you could help with with another problem I have here?
Maybe, I'm rusty @ chemistry
The question is A solution has a [OH−] of 1 x 10−12. What is the pOH of this solution?
Poh?
pOH apparently that's what it is. It doesn't say what it stands for...
Oh; take the negative log of 1x10^-12
The, to find PH from POH, subtract that from 14
I don't know why this works, but it's the procedure
is the answer 2 then?
lol you didn't post the answers
Oops sorry! The possible answers are 2 7 10 12
12
So, you punch this in your calculator: -(log(1e-12)) and you get 12
e stands for x10^
not to be confused with e, the number
Oh I understand!
so really -(log(1x10^(-12)))
And if you have to find PH next, just subract that from 14, and PH is 2
Unless you really love chemistry, it's best to just try to memorize these things and pass the course :P i hate it
I dislike it too and honestly I can't remember any of it. I guess I just really need to start working on that
Try to come up with tricks; like sulfite is just 'aiiight" cause it has one less oxygen than sulfate, which ate one more oxygen lol
haha Ok i'll be sure to use those tricks next time!
Just a brief mostly-math display of why pH + pOH = 14. If we agree that this relation of H3O+ and OH- holds: [H3O+] x [OH-] = 1x10^(-14) Then it follows by the negative logarithm of both sides that: -log( [H3O+]x[OH-] ) = -log(1x10^(-14)) By a logarithm property, log(ab) = log a + log b. We can simplify -log(10^(-14)) = 14. -log[H3O+] + -log[OH-] = 14 Note the remaining logarithms are the definitions of pH and pOH, respectively. pH + pOH = 14 But I do agree that memorizing this idea will probably be the best bet, primarily rewriting it as often as possible usually helps, or flash cards too sometimes..
It's looks complicated but I'm sure I'll get the hang of it thank you AccessDenied!
you're welcome! and i'm sure you will get it! :)
@AccessDenied Thanks! Now I understand why. :)
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