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Mathematics 7 Online
OpenStudy (anonymous):

The larger the pH scale value, the: higher the concentration of H3O+ ions lower the concentration of H3O+ ions lower the concentration of OH− ions more acidic the solution (I would say the more acidic the solution am I correct?)

OpenStudy (anonymous):

Hint: Higher concentration of H+ means lower pH and lower pH means it is more acidic.

OpenStudy (anonymous):

High Ph is basic

OpenStudy (anonymous):

It's a low concentration of hydronium ions. Just remember, high Ph = low hydronium; low ph = high hydronium.

OpenStudy (anonymous):

(hydronium = h30+)

OpenStudy (anonymous):

ohhh ok so if thats true then it's C?

OpenStudy (anonymous):

No, it's B.

OpenStudy (anonymous):

oh my bad!

OpenStudy (anonymous):

OH- would be high on a high ph value.

OpenStudy (anonymous):

I understand now thank you for your help again!

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

Do you think you could help with with another problem I have here?

OpenStudy (anonymous):

Maybe, I'm rusty @ chemistry

OpenStudy (anonymous):

The question is A solution has a [OH−] of 1 x 10−12. What is the pOH of this solution?

OpenStudy (anonymous):

Poh?

OpenStudy (anonymous):

pOH apparently that's what it is. It doesn't say what it stands for...

OpenStudy (anonymous):

Oh; take the negative log of 1x10^-12

OpenStudy (anonymous):

The, to find PH from POH, subtract that from 14

OpenStudy (anonymous):

I don't know why this works, but it's the procedure

OpenStudy (anonymous):

is the answer 2 then?

OpenStudy (anonymous):

lol you didn't post the answers

OpenStudy (anonymous):

Oops sorry! The possible answers are 2 7 10 12

OpenStudy (anonymous):

12

OpenStudy (anonymous):

So, you punch this in your calculator: -(log(1e-12)) and you get 12

OpenStudy (anonymous):

e stands for x10^

OpenStudy (anonymous):

not to be confused with e, the number

OpenStudy (anonymous):

Oh I understand!

OpenStudy (anonymous):

so really -(log(1x10^(-12)))

OpenStudy (anonymous):

And if you have to find PH next, just subract that from 14, and PH is 2

OpenStudy (anonymous):

Unless you really love chemistry, it's best to just try to memorize these things and pass the course :P i hate it

OpenStudy (anonymous):

I dislike it too and honestly I can't remember any of it. I guess I just really need to start working on that

OpenStudy (anonymous):

Try to come up with tricks; like sulfite is just 'aiiight" cause it has one less oxygen than sulfate, which ate one more oxygen lol

OpenStudy (anonymous):

haha Ok i'll be sure to use those tricks next time!

OpenStudy (accessdenied):

Just a brief mostly-math display of why pH + pOH = 14. If we agree that this relation of H3O+ and OH- holds: [H3O+] x [OH-] = 1x10^(-14) Then it follows by the negative logarithm of both sides that: -log( [H3O+]x[OH-] ) = -log(1x10^(-14)) By a logarithm property, log(ab) = log a + log b. We can simplify -log(10^(-14)) = 14. -log[H3O+] + -log[OH-] = 14 Note the remaining logarithms are the definitions of pH and pOH, respectively. pH + pOH = 14 But I do agree that memorizing this idea will probably be the best bet, primarily rewriting it as often as possible usually helps, or flash cards too sometimes..

OpenStudy (anonymous):

It's looks complicated but I'm sure I'll get the hang of it thank you AccessDenied!

OpenStudy (accessdenied):

you're welcome! and i'm sure you will get it! :)

OpenStudy (anonymous):

@AccessDenied Thanks! Now I understand why. :)

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