What value is a discontinuity of x squared plus 8 x plus 4, all over x squared minus x minus 6?
You are given \[\frac{x^2 + 8x + 4}{x^2 - x - 6}\] and asked to find the value of the discontinuity, correct?
yes
-1 -3 -3 or -2
how do you find the discontinuity
The discontinuity of the rational expression occurs where the numerator and denominator has common factors, correct?
Sure.
So its -2
And if we factor the rational expression completely we should be able to find those common expressions right?
Hmm, yes.
How did you arrive at -2? Would you mind explaining?
Because \(x^2 + 8x + 4\) doesn't appear to be factorable. Did you make a mistake while posting the expression?
Because it goes into 8 and 4?
-2 is correct, however, that's not the reason why.
\(x^2 + 8x + 4\) factors, just not over integers. Observe that \(\dfrac{x^2 + 8x + 4}{x^2 - x - 6} \) factors to \(\dfrac{(x - 2(\sqrt{3}-2))(x + 2(\sqrt{3} +2))}{(x - 3)(x + 2)}\)
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