Question

Check this? :)
The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible value for the width?
A. 40 cm
B. 19.2 cm
C. 16 cm
D. 8 cm

Answer 1

B

Answer 2

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Answer 3

I believe it is D.

Answer 4

@CrazyCountryGirl, would you mind posting how you arrived at B as the answer?

Answer 5

Sorry, typo! :) I mean D. Oh and this is her sister. :):):)

Answer 6

@Hero

Answer 7

I'm still curious as to what steps you took to arrive at your result.

Answer 8

I don't remember. This is old homework, that I forgot to turn in. It's not mandatory to, since school is over. I just wanna see if I was right. :)

Answer 9

@Hero

Answer 10

I'm just trying to make sure you understand how to do the problem on your own. When you post an answer, you're basically saying that you have also taken a set of steps to arrive at your answer. I'm just curious to know what those are. Furthermore, if you arrive at an answer, you shouldn't change it unless you are certain you have made a mistake.

Answer 11

Oh, ok. :) Thanks! I really don't remember how I got that though. Do you know if I got it right? D? If I didn't can you walk me through the steps to get it right?

Answer 12

So I'm right? 0_0

Answer 13

The formula for perimeter of a rectangle is
P = 2(l + w)

In this case we want P to be at most 96 and the length to be 5 times the width so:

\(96≥2(5w+w)\\96≥2(6w)\\96≥12w\\96/12≥w\\8≥w\)

Which means the greatest possible value of the width is 8 cm.