6.) the following function represents the profit P(n) in dollars that a concert promoter makes by selling tickets for n dollars each: P(n)=-250n^2+3,250n-9,000 Part A: What are the zeroes of the above function and what do they represent? Show your work. (4 points) Part B: Find the maximum profit by completing the square of the function P(n ). Show the steps of your work. (4 points) Part C: What is the axis of symmetry of the function P(n )?
You can see that as n gets very large, profit becomes negative. Profit is also negative when n is zero. The nature of this second degree (n^2) polynomial is a parabola. It has only one maximum when the derivative w.r.t. n is equal to zero. This occurs when 0 = -500n+3250
@Compassionate @tHe_FiZiCx99 @Zale101
You are given the function P(n) = -250n^2+3,250n-9,000.
In Part A you are asked to find the zeroes of the function, right?
oh I got part a already
I factored 0 = -250n^2+3,250n-9,000 and got -250(n-4) (n-9) which is the zero’s or solution of the function which represents the x intercepts.
Okay, Hang on, let me check that
is this the one you asked for my help on?
Okay, that looks good. In Part B, you are asked to find the maximum profit by completing the square, right?
yes
Okay, so to complete the square, we have to first put P(n) in the form Ax^2 + Bx = C right?
yeah
The first step is to Set P(n) = 0 so 0 = -250n^2+3,250n-9,000
Then add 9000 to both sides to get 9000 = -250n^2 + 3250n which is the same as -250n^2 + 3250n = 9000 Notice that has the same form as Ax^2 + Bx = C
Actually, if we divide both sides by -1 we get 250n^2 - 3250n = -9000 Now we have it in the form Ax^2 + Bx = C
Now we need to divide both sides by 250. After doing so we get n^2 - 13n = -36
At this point we have it in a form where we can complete the square. Do you agree?
yes
Do you remember what needs to be done in order to complete the square? What should we add to both sides?
you add a needed value to each side to balance the equation out @Hero
Once you have it in the form x^2 + bx = c, you complete the square by adding \(\left(\frac{b}{2}\right)^2\) to both sides.
In this case, b = -13 so we will add \(\left(\frac{-13}{2}\right)^2\) to both sides of \(n^2 - 13n = -36\).
Upon doing so we will have: \(n^2 - 13n + \left(\frac{-13}{2}\right)^2 = \left(\frac{-13}{2}\right)^2 - 36\)
Do you agree?
yeah
Do you know what that simplifes to?
simplify (-13/2)^2-36 to 25/4?
right @Hero
Yes, you correctly simplified the right side. What about the left side?
We need to write the left side as a binomial square.
n^2-13n- (13/2)?
Do you remember how to expand\(\left(\frac{-13}{2}\right)^2\)?
nope
Hint: \(\left(\dfrac{a}{b}\right)^2 = \dfrac{a^2}{b^2}\)
When you expand it, you get 169/4. That was correct.
oh okay wasn't for sure
However, I remembered, that you don't need to expand it on the left side because basically \(n^2 - 13n + \left(\frac{-13}{2}\right)^2\) = \(\left(n - \frac{13}{2}\right)^2\)
So what you end up with is \(\left(n - \frac{13}{2}\right)^2 = \frac{25}{4}\)
We have to keep solving for n, so what do you think we should to next?
well I know we have to iscolate the variable so im thinking we subtract from the side with the variable
@Hero
Actually, first we have to take the square root of both sides: \(\sqrt{\left(n - \frac{13}{2}\right)^2} = \sqrt{\frac{25}{4}}\)
What do you know about the relationship between a square and square root?
not much, ive just heard of them that's it
why @Hero
n= 4 and 9 @Hero
is that right
You solved for n the rest of the way? Can you show the steps you took to find n?
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