If a vector has an initial point of (2,6) and a terminal point (14,11). Out of 5, 11, 12, and 13, what is closest to the magnitude of the vector?

Question

e.mccormick · Answer

Know how to find the magnitude?

anonymous · Answer

Use the distance formula.

anonymous · Answer

The distance between the points will give the magnitude of the vector.

e.mccormick · Answer

Distance formula, aka Pythagorean Theory applied to distance:
$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The magnitude of a vector is equal to the distance it travels.

e.mccormick · Answer

Well, that was some interesting lag.

ashleyisakitty · Answer

I did the distance formula, and I believe the answer is 12. Is that true?

e.mccormick · Answer

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$D=\sqrt{(14-2)^2+(11-6)^2}$

$D=\sqrt{(12)^2+(5)^2}$

$D=\sqrt{144+25}$

$D=\sqrt{169}$

Find your mistake?