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Mathematics 16 Online
OpenStudy (anonymous):

Solve for y 2y+2x=4

OpenStudy (anonymous):

Looking for an explanation of how to solve for y, not just the answer. (Divide everything by 4? by 2? Help please) Thanks!

OpenStudy (anonymous):

y=2-x

OpenStudy (johnweldon1993):

Well we start with \[\large 2y + 2x = 4\] the first thing we want to do...is move everything that ISN'T 'y' to the other side of the equation...so here....we have a 2x on the same side as the 2y....so lets subtract 2x from both sides of this equation \[\large 2y + 2x \color \red{- 2x} = 4 \color \red{- 2x}\] now we have \[\large 2y = 4 - 2x\] Alright...now we want to solve for 'y'....we have 2y...so we divide EVERYTHING by 2.... \[\large \frac{2y}{2} = \frac{4 - 2x}{2}\] which will become \[\large y = 2 - x\] but we will always want to write this with the 'x' in front of the constant...so lets write it as \[\large y = -x + 2\]

OpenStudy (anonymous):

Thank you ^

OpenStudy (johnweldon1993):

No problem :)

OpenStudy (anonymous):

One more question, if you are still available @johnweldon1993 . This is a linear equation that I am suppose to graph. How do I get the slope? (y=mx+b) I assume it's just 1 or -1, but I could be confused.

OpenStudy (johnweldon1993):

No you got it... the form \[\large y = mx + b\] is slope intercept form....'m' is the slope...and since our equation is \[\large y = -x + 2\] our 'm' would be -1

OpenStudy (anonymous):

And since slope is always written as a fraction (rise/run), would it be written as -1/1 ?

OpenStudy (johnweldon1993):

Well...yes...but as you can see \[\large \frac{-1}{1} = -1\] It Is good to write it like that if you are not comfortable with seeing just -1 as a slope...but either way is correct

OpenStudy (anonymous):

Oh, duh. Thank you for your help, I appreciate it.

OpenStudy (johnweldon1993):

anytime :)

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