Question

a country's population in 1992 was 103 million in 1997 it was 108 million estimate the population in 2004 using the exponential growth formula round your answser to the nearest million
p=Ae^kt

please help !

Answer 1

if you have to use
\[P=Ae^{kt}\] you need to find \(k\) first

Answer 2

\(A\) is the starting amount, which in your case is \(103\) so it is going to be
\[P=103e^{kt}\]
if \(t=5\) you know \(P=108\) so you can solve for \(k\) via
\[\large 108=103e^{5k}\]