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a country's population in 1992 was 103 million in 1997 it was 108 million estimate the population in 2004 using the exponential growth formula round your answser to the nearest million p=Ae^kt please help !
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if you have to use \[P=Ae^{kt}\] you need to find \(k\) first
\(A\) is the starting amount, which in your case is \(103\) so it is going to be \[P=103e^{kt}\] if \(t=5\) you know \(P=108\) so you can solve for \(k\) via \[\large 108=103e^{5k}\]
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