What is the factored form of b(2) + 12b + 32?
Do you mean: \(b^2+12b+32\)?
yes
(b-8) (b-4)
This is a FOIL problem in reverse.\[ b^2 + 12b + 32=(b+8)(b+4)\]
You guys might want to expand on that.
The eight and four multiply to 32 and add to 12.
how do I solve this not just the answer
ok thankyou
@AnimalAin Just gave a small explanation on how.
can you guys help me on another one
Sure.
What is the factored form of 4k2 + 20k + 25?
This one is a little more complicated. We need to use the ac method, since the leading coefficient (in this case, four) isn't one. Remember our general representation of a quadratic function y = ax^2 + bx + c First, find the product of a and c. In this problem, that would be four times twenty-five, which equals 100. Now find the factorization of 100 that adds to twenty. I think it is ten and ten ( 10 times 10 is 100; 10 + 10 = 20). Rewrite the expression as follows:\[4k^2 + 20k + 25=4k^2 + 10k+10k + 25\]Now factor by grouping.
\[4k^2 + 20k + 25=4k2 + 10k+10k + 25=2k(2k +5)+5(2k +5)=(2k+5)^2\]
Actually, if I had been more observant, I would have recognized that it was a perfect square at the start, and saved myself a bunch of work. Live and learn...
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