Garrett throws a dart at a circular dart board. The dart board has a radius of 18 inches, and the bull’s eye in the center of the dart board has a radius of 4 inches. What is the probability that a dart thrown at random within the dartboard will hit the bull’s eye? Round your answer to the nearest tenth, if necessary.
Find the area of the board (this will be your sample space) and area covered by the bull's eye (this will be numerator for calculating probability)
How would i do that?
area of circle = \(\Large \pi r^2\)
for the board, radius = 18 for the bull's eye, radius = 4
so i would do it like this? \[\frac{ 4^2\pi }{ 18^2\pi }\]
yes, correct. pi gets cancelled out
if you want your final answer in %, then multiply the above result by 100
so this? \[\frac{ 4 }{ 18 }\times100?\]
no... did you ignore the squares ? \(\Large \frac{ 4 ^2}{ 18^2 }\times100\)
Oh yea sorry i forgot
but i got 4.93 is that right?
4.938% or 4.94 % yes thats correct!
Thanks Hartnn ;)
welcome ^_^
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