Question

Please help me out..

Answer 1

y=ln x
e^y=e^ln x
e^y=x

Answer 2

Same concept as above. Opposite of Ln is e so
\[c = \ln 4\] if we raise e to both sides we get\[e^c=e ^{\ln4}\]
Then ln and e cancel out leaving\[e^c=4\]

Answer 3

Am I right?

Answer 4

Correct!

Answer 5

This one?

Answer 6

u should ask here

Answer 7

Correct!

Answer 8

How do I figure this one out?

Answer 9

Well now that we know the opposite of LN is e then the opposite of e should be LN

Answer 10

\[67.21=e^a\]

Answer 11

if we take the natural log of both sides\[\ln 67.21 = \ln e^a\]

Answer 12

the ln cancels out with the e and we are left with \[\ln 67.21 = a\]

Answer 13

Am I correct?

Answer 14

Well we know the relationship \[\log_ba=c \]=\[b^c=a\]

Answer 15

a log by itself will actually mean\[\log _{10}\]

Answer 16

ohhh so D!

Answer 17

so you really have \[\log _{10}200=a\]

Answer 18

correct!

Answer 19

I have no idea...

Answer 20

I am not sure either but i believe it is the common logarithm

Answer 21

Am i right?

Answer 22

Correct! it is false

Answer 23

correct?

Answer 24

Correct

Answer 25

Correct?

Answer 26

The opposite of e is ln so it can not be log

Answer 27

\[e^a = 28.37\]

Answer 28

If we take the ln of both sides then we have\[\ln e^a = \ln 28.37\]the ln and e cancel out on the left leaving us with \[a= \ln 28.37\]

Answer 29

or \[\ln 28.37 = a\] they mean the same thing

Answer 30

Thank you so much!:) I'll use your help again! have a wonderful night.

Answer 31

My pleasure, I look forward to it. Enjoy your night