Question

An object is positioned in front of a concave mirror between the center of curvature and the focal point. Click on the ray diagram that shows the proper positioning of the image.

Answer 1

@shamim

Answer 2

Well, the answer should be C. It follows from the equation :
\[1/V +1/U =1/F=2/R\],
V=image distance, U=object distance, F= focal length, R=radius of curvature

in this equation,if you put any values of u between F and 2F, since R=2F, and by your question, object distance is between focus and center of curvature, you will always get a value of image distance which is greater than the radius of curvature from the pole of the mirror.
Now by finding out the magnification by the equation, \[m=-{v/u}\], you will get a negative value of magnification which means the image will be inverted.
So, C is the logical option.

Note: Use proper sign conventions.

Answer 3

thanks!

Answer 4

U R WELCOME!