Monochromatic light of 605 nm falls on a single slit of width 0.095 mm. The slit is located 85 cm from a screen. How far from the center is the first dark band?
\[y = ( m + 1/2) \lambda L/d\]
Here... m=1 for first dark fringe.. L is the distance of the screen from slit
d is the width of the slit, and lambda is the wavelength.
You can use the same equation as for two slids, which is \[\frac{\Delta x}{d}=\frac{k \cdot \lambda}{g}\] \[ \Delta x \] is what you're looking for, lamda is the wavelength, g the width of your slit and d the distance between slit and screen. The difference to two or more slits is, that u dont find the bright, but the dark bands.
\[y = ( 1 + 0.5)(605 \times 10^{-9} )(0.85) / ( 0.095 \times 10^{-3}\]
\[Y = 8.11 \times 10^{-3}\]
I came up with 0.008119737
If it helps its on of these 4. I just need to understand these questions better its on my review sheet. 0.5 mm 5.4 mm 540 mm 5,400 mm
and, as a proper physicist, don't forget your units
This is for a review. I just want to grasp these questions better. If it helps its one of these. 0.5 mm 5.4 mm 540 mm 5,400 mm
OF that queston your and my answer are same.
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