Solve the equation Check the solution. −2/x+4 = 4/x+3
\[\large \frac{-2}{x + 4} = \frac{4}{x + 3}\] like that right?
\[\frac{ -2 }{ x+4 } = \frac{ 4 }{ x+3 }\]
yes!
Alright lol....well we can begin by cross multiplying!
everyone alsways wants to solve the cute girls question lol
sooo multiply -2 and what? lol
|dw:1400708614593:dw| like that
So it would be -2 times the (x + 3) and also the 4 times the (x + 4) so now we will have \[\large -2(x + 3) = 4(x + 4)\] right?
ohhh. okay okay i see. one sec
okay whats next
Well now we solve for 'x' Start by distributing the -2 and the 4 into those parenthesis...
ummm....x+-6 = x+24
??
Not quite....so we had \[\large -2(x + 3) = 4(x + 4)\] right? so what we do...is distribute the -2 into those parenthesis... We take the -2....and multiply it by every term inside the parenthesis...so we will have \[\large -2x - 6 = 4(x + 4)\] make sense? and now we do the same thing for the 4...
ohh duh. lol so -2x-6 = 4x+24
Hmm....4 times 4 is what again?
omg..wow. 16
haha you're doing good ;P Alright great! so we have \[\large -2x - 6 = 4x + 16\] Now to combine like terms...we want all the terms with an 'x' on 1 side of the equation....and the other ones on the other side
We can do that by adding 2x to both sides of the equation....and then subtracting 16 from both sides of the equation... what do we have after doing that?
divide -22by6
Yes! which is?
-3.7
i need it to be an improper fraction
Great!...so we know that \[\large x = -3.7\] now we check it... And oh okay...then -22/6 it is....but that can be simplified a bit right?
wait.. how did you get the improper fraction?
Remember how you said the next step would be "divide -22 by 6" ? :)
That is the fraction... \[\large x = \frac{-22}{6}\]
yes i know but how to you turn -3.7 into an improper fraction...
i understand that -22/6 IS the improper fraction. but how did you get that
I'm not sure what you mean... alright...lets put it like this... We knew to solve for 'x'....we would divide -22 by 6 When you DO divide -22 by 6...you get the -3.7 \(\large \frac{-22}{6} = \)improper fraction version when you actually DO -22 divided by 6...you get \(\large -3.7 =\) decimal version
the only thing that we did...was go back 1 step... instead of actually doing the calculation of -22/6 (which comes out to the -3.7 you said) we just left it as the -22/6
ohhhh >_< okay okay
lol don't worry about it hun you're fine :) alright...alright....we have \[\large x = \frac{-22}{6}\] right? but...that can be simplified a bit (not calculated...but simplified)
-11/3
and thats my answer. right?
Perfect! that is your improper fraction...and that is your answer :)
can you help me with another?
im gonna tag you in the question
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