Find the work in ft-lbs required to empty a full hemispherical tank w/ a radius of 6 ft by pumping the water to 2 ft above the top of the tankk
@sleepyhead314
>.> I still don't know how to help with this hemispherical stuff...
k let's do the last few and get back to this
im here
This is probably gonna be wrong... 62.4pi times the integral from 0 to 6 of (-72y + 6y^2 + y^3) dy
yeah... I don't think I did it right, sorry
hold on
it has to be pi again but i don't think it's a big negative number. this one is kind-of negative
i got -105859
try it from here that'll be the format http://prntscr.com/3leq0z plug in 6 for R
i got pi*y^4
... plug in 6 for R that'll give you the type of stuff I'll usually have you plug in http://www.wolframalpha.com/input/?i=62.4pi+times+the+integral+from+0+to+6+of+%2872x+-+18x%5E2+%2B+x%5E3%29+dx
62515.5 and in pi would be?
just try that, I'm not sure why it's not showing up with a pi
k wait
he said no. i tried rounding
sorry, but I've gtg now :( good night. try looking through hero's work look for where he got his numbers and stuff good luck good night
i'll get in touch with me thanks for your time and help
him*
@Hero
@satellite73 @ganeshie8
do you have a pic?
there's no picture. that's all i have
wait
hero gave me this: http://assets.openstudy.com/updates/attachments/537d3749e4b015d57c6438e6-hero-1400719958596-workftlbs.png
My English is not good, so that I want to make sure that I understand the problem. pump the water into or out of the hemisphere?
out
so, the hemispherical tank is not empty then, right? just lost amount of water only. And our duty is find out the work done on pumping out process, right?
yes to 2ft above the top of the tank
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