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Mathematics 18 Online
jigglypuff314 (jigglypuff314):

Find the work in ft-lbs required to empty a full hemispherical tank with a radius of 4 ft, by pumping water to the top of the tank. please help? its just a curiosity question, way above my own lvl, so really simple english would be nice xP

jigglypuff314 (jigglypuff314):

@jdoe0001 @Loser66 @thomaster @Hero @tkhunny could any of u help or know someone that could help :3

jigglypuff314 (jigglypuff314):

I'm on the app so I can't even bump >.<

jigglypuff314 (jigglypuff314):

@Hero do u have any idea? :/

hero (hero):

The Work Formula For Emptying A Tank is: \[\text{Work} = D \int_{a}^{b}A(y)[H - y]dy\] where \(D\) is the Density \(A(y)\) is the cross sectional area \(H\) is the height

jigglypuff314 (jigglypuff314):

alright, that makes sense so far, but I'm slightly confused on how to get the A(y)

OpenStudy (anonymous):

it has something to do with radius i think

jigglypuff314 (jigglypuff314):

yeah xD it might be the area of a circle formula, since you r taking an infinite number of thin slices of circles from the hemisphere? but idk how that would work in this case?

jigglypuff314 (jigglypuff314):

@Hero so would it be something like 9810pi times integral from -4 to 0 of (16-x^2)(-x) dx ? :/

OpenStudy (anonymous):

@FibonacciChick666

OpenStudy (fibonaccichick666):

A(y) is the area of the thing, so what is half of the area of the basin?

OpenStudy (fibonaccichick666):

not half, just area

jigglypuff314 (jigglypuff314):

32pi ? cuz volume of sphere is 4 pi r^2

jigglypuff314 (jigglypuff314):

or 64pi :/

OpenStudy (anonymous):

...well this is confusing as heck to me... but i'll try o.e

OpenStudy (anonymous):

ok what did you need, jeff?

OpenStudy (anonymous):

helping answering this

OpenStudy (anonymous):

ok, hold on

OpenStudy (anonymous):

W = ∫ F · ds = 62.4 π ∫ (8-y) (36 - (6-y)²) dy [0,6] ............ water = 62.4 lbs/ft³ = (62.4 π) y²/12 (3y² - 80y + 576) ...... from 0 to 6 = (62.4 π) 3 (108 - 480 + 576) = 62.4 π (612) ≈ 119973.6535 ft-lbs Answer: ≈ 119973.6535 ft-lbs (not sure is this is the right one... or not)

OpenStudy (anonymous):

yea something like that

jigglypuff314 (jigglypuff314):

where'd u get those numbers from??? all they gave was a radius of 4

OpenStudy (anonymous):

like i said... (not sure is this is the right one... or not)

OpenStudy (anonymous):

im not sure i understand this too well

OpenStudy (anonymous):

me either o-o mathematical equations r my arch enemies...

OpenStudy (anonymous):

right?

jigglypuff314 (jigglypuff314):

well, thanks for trying at least :)

OpenStudy (anonymous):

Yeah- no probs xD

hero (hero):

OpenStudy (anonymous):

it's wrong because i think it has to have a pi in it

jigglypuff314 (jigglypuff314):

OMG thank you hero! <3

jigglypuff314 (jigglypuff314):

he multiplied by pi in the last step, look at the step before, jeff

OpenStudy (anonymous):

sry I don't get it jiggles so sry I just don't now so here a medal for it

OpenStudy (anonymous):

that final answer is not it

hero (hero):

@jeffsours, if you have a better solution post it.

OpenStudy (anonymous):

i don't but i texted teacher's hotline it's not it and its confusing me.

OpenStudy (anonymous):

so how ya guys doing

hero (hero):

If you haven't performed the steps yourself how do you know what is right and what isn't?

hero (hero):

The second to last step is written in pi format.

OpenStudy (anonymous):

can you stop spammers pls hero

OpenStudy (sleepyhead314):

I told ya to look at the step before the last, jeff 62.4 times 64 times pi -> 3993.6pi

OpenStudy (anonymous):

so it's 3993.6 pi?

jigglypuff314 (jigglypuff314):

I did a full read, there were no mistakes in hero's work

OpenStudy (sleepyhead314):

yes...

OpenStudy (sleepyhead314):

did you even look through the work jeff? hero worked hard to write it out for us, try to read it carefully

OpenStudy (anonymous):

i did and i'm not getting it but it seems right

OpenStudy (sleepyhead314):

yes. all throughout D = 64 which he plugged in in the second to last step and there was a pi next to it.

OpenStudy (sleepyhead314):

what no, I was saying 64pi was in it, not that it was the answer.

OpenStudy (sleepyhead314):

it should be 3993.6pi

OpenStudy (anonymous):

yea its correct you guys I found the answer on a website on http://mathehelp.com

OpenStudy (anonymous):

omg hero i'm not a troll he made it 4000pi now please unban my other account

jigglypuff314 (jigglypuff314):

I would like to apologize for any inconveniences from my asking this question. I had been genuinely interested in learning and understanding how to answer such question myself, so thank you @Hero for helping with the step by step and helping me gain a better understanding of the type of thinking required to get through a problem like this in the future, thank you.

OpenStudy (anonymous):

i apologize also

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