Find the work in ft-lbs required to empty a full hemispherical tank with a radius of 4 ft, by pumping water to the top of the tank. please help? its just a curiosity question, way above my own lvl, so really simple english would be nice xP
@jdoe0001 @Loser66 @thomaster @Hero @tkhunny could any of u help or know someone that could help :3
I'm on the app so I can't even bump >.<
@Hero do u have any idea? :/
The Work Formula For Emptying A Tank is: \[\text{Work} = D \int_{a}^{b}A(y)[H - y]dy\] where \(D\) is the Density \(A(y)\) is the cross sectional area \(H\) is the height
alright, that makes sense so far, but I'm slightly confused on how to get the A(y)
it has something to do with radius i think
yeah xD it might be the area of a circle formula, since you r taking an infinite number of thin slices of circles from the hemisphere? but idk how that would work in this case?
@Hero so would it be something like 9810pi times integral from -4 to 0 of (16-x^2)(-x) dx ? :/
@FibonacciChick666
A(y) is the area of the thing, so what is half of the area of the basin?
not half, just area
32pi ? cuz volume of sphere is 4 pi r^2
or 64pi :/
...well this is confusing as heck to me... but i'll try o.e
ok what did you need, jeff?
helping answering this
ok, hold on
W = ∫ F · ds = 62.4 π ∫ (8-y) (36 - (6-y)²) dy [0,6] ............ water = 62.4 lbs/ft³ = (62.4 π) y²/12 (3y² - 80y + 576) ...... from 0 to 6 = (62.4 π) 3 (108 - 480 + 576) = 62.4 π (612) ≈ 119973.6535 ft-lbs Answer: ≈ 119973.6535 ft-lbs (not sure is this is the right one... or not)
yea something like that
where'd u get those numbers from??? all they gave was a radius of 4
like i said... (not sure is this is the right one... or not)
im not sure i understand this too well
me either o-o mathematical equations r my arch enemies...
right?
well, thanks for trying at least :)
Yeah- no probs xD
it's wrong because i think it has to have a pi in it
OMG thank you hero! <3
he multiplied by pi in the last step, look at the step before, jeff
sry I don't get it jiggles so sry I just don't now so here a medal for it
that final answer is not it
@jeffsours, if you have a better solution post it.
i don't but i texted teacher's hotline it's not it and its confusing me.
so how ya guys doing
If you haven't performed the steps yourself how do you know what is right and what isn't?
The second to last step is written in pi format.
can you stop spammers pls hero
I told ya to look at the step before the last, jeff 62.4 times 64 times pi -> 3993.6pi
so it's 3993.6 pi?
I did a full read, there were no mistakes in hero's work
yes...
did you even look through the work jeff? hero worked hard to write it out for us, try to read it carefully
i did and i'm not getting it but it seems right
yes. all throughout D = 64 which he plugged in in the second to last step and there was a pi next to it.
what no, I was saying 64pi was in it, not that it was the answer.
it should be 3993.6pi
yea its correct you guys I found the answer on a website on http://mathehelp.com
omg hero i'm not a troll he made it 4000pi now please unban my other account
I would like to apologize for any inconveniences from my asking this question. I had been genuinely interested in learning and understanding how to answer such question myself, so thank you @Hero for helping with the step by step and helping me gain a better understanding of the type of thinking required to get through a problem like this in the future, thank you.
i apologize also
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