Question

thank you

Answer 1

@jim_thompson5910 could you help with this possibly? :)

Answer 2

All you're doing here is plugging theta = 25 into the function to find out how far the object is when the angle is 25 degrees

Answer 3

The same is said about theta = 55

Answer 4

So how would I write the function? @jim_thompson5910

Answer 5

the function is already given

Answer 6

d = 94 sec θ

Answer 7

Ahh okay. So d = 94 sec 25? I'm somewhat confused to write. @jim_thompson5910

Answer 8

then you evaluate that

Answer 9

keep in mind that sec(theta) = 1/cos(theta)

Answer 10

so your function of

\[\Large d = 94\sec(\theta)\]

is equivalent to

\[\Large d = \frac{94}{\cos(\theta)}\]

Answer 11

Okay. Then I plug in the 25 by the cos?

Answer 12

yes

Answer 13

When I enter 25 and cos I get 0.906. Is that right?

Answer 14

\[\Large d = \frac{94}{\cos(\theta)}\]

\[\Large d = \frac{94}{\cos(25)}\]

\[\Large d = \frac{94}{0.906}\]

so far, so good

Answer 15

94/0.906 = 103.752759381899

so if you were rounding to 3 places, it'd be 103.753

but you should type all of 94/cos(25) to make sure you don't get roundoff error

Answer 16

no once you're done evaluating, you can move onto plugging in theta = 55

Answer 17

So there's more to do with 103.753?

Answer 18

no that's the approximate distance d for theta = 25

Answer 19

Look good?

Answer 20

yes it does

Answer 21

nice work

Answer 22

Thanks for the help!

Answer 23

you're welcome