Question

Solve 2x2 - 12x + 20 = 0

I know I'll have to factor it, and that it will end with an imaginary number as well, any help???

Answer 1

\(\large 2x^2 - 12x + 20 = 0\implies
\begin{array}{llll}
2(x^2&-6x&+10)=0\\
&\quad \uparrow &\quad \uparrow \\
&-3-2&-3\cdot -2
\end{array}\)

Answer 2

hmmm wait.... shoot.. ahemm -3-2 is -5... ok

Answer 3

hehhe

Answer 4

well, here are the options :
3 ± i

3 ± 2i

1 ± 2i

2 ± 3i

Answer 5

which one would it be ?

Answer 6

have you covered the quadratic formula yet?

Answer 7

yeah, do I need to use that to solve it then ? (if so, how ? )

Answer 8

\(\bf 2x^2 - 12x + 20 = 0\implies2(x^2-6x+10)=0\implies x^2-6x+10=0
\\ \quad \\

\textit{quadratic formula}\\
{\color{blue}{ 1}}x^2{\color{red}{ -6}}x{\color{green}{ +10}}
\qquad \qquad
x= \cfrac{ - {\color{red}{ b}} \pm \sqrt { {\color{red}{ b}}^2 -4{\color{blue}{ a}}{\color{green}{ c}}}}{2{\color{blue}{ a}}}\)