A beam rests against a wall, forming a 50° with the floor. Use the function y = 9 sec θ to find the length of the beam to the nearest tenth of a foot.
Ok
just imput the value of 50 into the equation and hit on the calculator and walah it gives it to you exactly unless you need it in radians.
do you need radians or degrees?
hit on the calculator... too bad it probably doesn't have sec in it... so... Geogebra? lol or should we just take the *reciprocal of cosine*? ;)
so i take the reciprocal of cos50?
That is correct... and then multiply it by 9 :) Be careful, though, and heed @magbak DO make sure that your calculator is set to DEGREES and not RADIANS... or we might face some... complications ;)
Ok so you can take the reciprocal of cosine and then you multiply by 9.
I ment you beat me to it.
So in the end you do need to use the calculator.
ok im so stumped right now How do i find the reciprocal of cos 50? o.o
Input \[\Large \frac1{\cos(50^o)}\]
i tried that and it came out weird
They usually do... what comes out?
he alwayse beats me to it
You've got to type faster, old timer :P
i got 1.55
it come out to be 1.555
That's right, alley... Why are you so scared of weird numbers? :D
Even \(\large \pi\) is a weird number :D
it is 3.14157124
No it isn't D: It's 3.1415926535897932384626433832795028841... XD
So 14.001 would be the length of the beam?
Ill let him answer this one
Yes, Alley, you got it ;)
Thanks guys :)
No prob
Only 10 more i need help with xD but if you dont want to its cool
no ill help you as much as you need bae
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