cos theta-tan theta cos theta=0
a. 0, pi/4, pi, 5pi/4
b.pi/4, 5pi/4
c. pi/2, 3pi/4, 3pi/2, 7pi/4
d. pi/2, 7pi/6, 3pi/2, 11pi/6
I believe the answer is b but im not positive
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OpenStudy (tanya123):
B.pi/4, 5pi/4
OpenStudy (anonymous):
are you positive? @tanya123
OpenStudy (tanya123):
Yes.
OpenStudy (anonymous):
could you help me with another? if you dont mind? @tanya123
OpenStudy (anonymous):
4cos theta + 1= 2cos theta
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OpenStudy (tanya123):
Sorry I don't know this one, but I think he could help you @jim_thompson5910
OpenStudy (anonymous):
@jim_thompson5910 can you help?
jimthompson5910 (jim_thompson5910):
think of cos(theta) as 'z'
so we really have this equation
4z + 1 = 2z
solve for z to get ???
OpenStudy (anonymous):
2?
jimthompson5910 (jim_thompson5910):
no
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jimthompson5910 (jim_thompson5910):
4z + 1 = 2z
4*2 + 1 = 2*2
8 + 1 = 4
9 = 4 ... that equation is false, so z = 2 is not the solution
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jimthompson5910 (jim_thompson5910):
don't worry about the final answer
right now, we're just focusing on solving for z
OpenStudy (anonymous):
you know what, im missing part of this problem.
what values for theta(0greater than or equal to theta greater than or equal to 2 pi) satisfy the equation
im not sure if that makes a difference
jimthompson5910 (jim_thompson5910):
it does, but not for this bit when solving for z
OpenStudy (anonymous):
2z=-1
z=-2
jimthompson5910 (jim_thompson5910):
2z = -1 is right
z = -2 is NOT correct
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OpenStudy (anonymous):
hmm -1/2?
jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
we made z = cos(theta)
so what we really have is cos(theta) = -1/2
jimthompson5910 (jim_thompson5910):
use a unit circle to solve for theta in cos(theta) = -1/2
OpenStudy (anonymous):
im sorry, I don't really understand how use the unit circle
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jimthompson5910 (jim_thompson5910):
do you have a unit circle with you?
OpenStudy (anonymous):
yes
jimthompson5910 (jim_thompson5910):
look for points on the unit circle that have an x coordinate of -1/2
jimthompson5910 (jim_thompson5910):
what's the angle that's associated with them (in radians)?
OpenStudy (anonymous):
in quadrant III and II
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jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
you're in the right quadrants
OpenStudy (anonymous):
awesome, so what next
jimthompson5910 (jim_thompson5910):
locate the point in quadrant 2 has an x coordinate of -1/2
what is the angle of this point?
OpenStudy (anonymous):
120 and 240
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jimthompson5910 (jim_thompson5910):
120 is in quadrant 2
240 in quadrant 3
those are the degree angles
what about the radian angles?
OpenStudy (anonymous):
2pi/3 and 4pi/3
jimthompson5910 (jim_thompson5910):
correct
OpenStudy (anonymous):
so is that my answer?
jimthompson5910 (jim_thompson5910):
yes, those are the solutions to 4cos(theta) + 1 = 2cos(theta)
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jimthompson5910 (jim_thompson5910):
where 0 <= theta < 2pi
OpenStudy (anonymous):
thank you so much!
OpenStudy (anonymous):
could you check the answer to my first question to make sure it is right?