Help me i will award medal and fan! The population of a local species of dragonfly can be found using an infinite geometric series where a1 = 42 and the common ratio is three fourths. Write the sum in sigma notation and calculate the sum that will be the upper limit of this population.
the summation of three fourths times 42 to the i minus 1 power, from i equals 1 to infinity.; the sum is divergent. the summation of three fourths times 42 to the i minus 1 power, from i equals 1 to infinity.; the sum is 168. the summation of negative 42 times three fourths to the i minus 1 power, from i equals 1 to infinity.; the sum is divergent. the summation of negative 42 times three fourths to the i minus 1 power, from i equals 1 to infinity.; the sum is 168.
Those are my answer choices
actually hold on... -_-
haha okay and it wants to know if its divergent or the sum is 168
cant believe i have kirbykirby working on my problme xD
Well it will be convergent for sure since the ratio is a fraction less than 1
oh true so that removes two of the answer choices
Actually, before I continue.. does your prof write the geometric series starting from \(a_1\) or \(a_0\)? Like do they write \(a_0+a_1+a_2+...\) or \(a_1+a_2+...\) This will make a difference
No i wouldnt think so since i am in highschool, so im pretty sure they dont do that
?
Which one do they use
usually a1
i have never seen a0
ok
The geometric series is written as: \[\large 42+42\left( \frac{3}{4}\right)+42\left( \frac{3}{4}\right)^2+42\left( \frac{3}{4}\right)^3+...\\ =\large a_1+a_1r+a_1r^2+a_1r^3+...\\ =\large a_1+a_2+a_3+a_4...\] Now, the geometric series in sigma notation is written as: \[ \large\sum_{i=0}^{\infty}a_1r^i\] \[\large \sum_{i=0}^{\infty}42\left(\frac{3}{4} \right)^{i}=\sum_{i=1}^{\infty}42\left( \frac{3}{4}\right)^{i-1} =\large \frac{42}{1-\frac{3}{4}}\]
Thank you so much this was so helpful, you earned yourself a fan and a medal
:) np
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