Question

I will give you a medal!! Please?

Find the x-intercepts of the parabola with vertex (1,20) and y-intercept (o,16). Write your answer in this form: (x1,y1),(x2,y2). If necessary, round to the nearest hundredth.

Answer 1

vertex us \((1,20)\) means it looks like
\[y=a(x-1)^2+20\]

Answer 2

if the \(y\) intercept is \((0,16)\) then we can solve for \(a\) vial
\[a(-1)^2+20=16\] or
\[a+20=16\]making \[a=-4\]

Answer 3

your parabola is therefore
\[y=-4(x-1)^2+20\]

Answer 4

that is not the end of the question, you still have to find the zeros, but at least you know what to find the zeros of
you good from there?

Answer 5

nooot really.. I didn't understand anyof that.. I swear if I pass this test.. I will do anything for you.

I am not good with this stuff

Answer 6

(9,0),(-1,0)?

Answer 7

im scared to try it cause I dont wanna miss the problem

Answer 8

Is it multiple choice?

Answer 9

noo..
fill in the blank.

Answer 10

fuuuuuuuuuuuudgee.... it was wrong..

Answer 11

This has the same answer I do! :) Hope this helps. http://www.algebra.com/algebra/homework/Quadratic-relations-and-conic-sections/Quadratic-relations-and-conic-sections.faq.question.638113.html

Answer 12

Really?

Answer 13

Thats not the same problem babe..

Answer 14

Wow that's screwed up.. Im so sorry.. :(

Answer 15

its okay hun!

Answer 16

Im trying to figure out how to do it but wow im kinda lost but ill keep trying and if I think I got it Ill let you know but I don't wanna give you wrong info sorry =( I suck

Answer 17

its okaay