can someone please help only have 2 hours til deadline
I can help you with the second one cause the first one won't open...
ok thank you
1.a)\[A=a^2\] a=the side \[A=18^2\] So what is A?
i dont know i have that to but i don know where to go on from that
What is\[18\times18\]
\[18\times18=324\]
so a =324?
Yes.
ok thank you can you help me with any of the other questions
1.b)\[V = \frac{ bh }{ 3 }\]
\[Volume=\frac{ 20\times18 }{ 3 }\]
Volume=120
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we have a right triangle so we can use our trig functions
also we have 1 side and 2 angles so we can easily find the 3rd angle
to find the missing angle we do \[\angle = 180 - 90 - 49 = 41 degrees\]
Using that angle we can find the height of the plank using the function \[Cos \theta = Adjacent/ Hypotenuse\]
\[Cos(41) = 3 / x\] From there we see our angle is 41 the adjacent side is the ground and the hypotenuse it the plank so now to find the side just solve for x
To find the wall, using the same angle we would use\[Tan \theta = Opposite/Adjacent\] Seeing as our angle is 41 the opposite side of that is the wall and the adjacent side is the ground we now have \[Tan(41) = x/3\] now you just solve for x
OK and then what
Once you solve for both of those X values you will have your answers
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