Question

If P (A) = 0.2 and P (B) = 0.3 and A and B are disjoint, what is P (A or B)?

0.00
0.06
0.10
0.44
0.50

Answer 1

@satellite73

Answer 2

p(A or B) =p(A)+p(B) -P(A and B)
but here since A and B are disjoint hence we can say P(A and B) =0
so here
p(A or B) =p(A)+p(B)
=0.2+0.3 =0.50

Answer 3

Thank you! I'll give you a medal, can you help with this one?

If P (A) = 0.2 and P (B) = 0.3 and A and B are independent but NOT disjoint, find P (A or B).

0.06
0.10
0.44
0.50
Cannot be determined from the information given.

Answer 4

@matricked

Answer 5

@tabicyrus
It seems medals are more dear to u....?

Answer 6

no but some people wont help unless I give a medal :(

Answer 7

\[P(A\cup B)=P(A)+P(B)-P(A\cap B)\]
P(A or B) = 0.2 + 0.3 - (0.2 * 0.3) = you can calculate

Answer 8

0.1?

Answer 9

\[0.2+0.3-(0.2\times0.3)=?\]

Answer 10

@tabicyrus
Oh i see..
but you shouldn't say. that way...

Answer 11

okay now i got .44

Answer 12

@tabicyrus You are correct :)

Answer 13

thank you! @kropot72 :)

Answer 14

You're welcome :)