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|z-i| = 3 defines a circle in the complex plane, find radius and centre.
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i know the radius is 3, not sure how to find the centre though
There is formula :P well basically you treat the x as real and y as imaginary |z-(0x + i)| therefore centre is?
:o 0,1?
yea lol
wow that was easy..lol thx
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whats the formula btw?
z=x+iy
Errrr...... Nvm bout that haha. well z= x + yi so |(x-0)+i(y-1)| Now you can clearly see its (0,1)
continue lol
:o ok. ty
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np :) i would like to see the rest of complex analysis Qn :)
o, thats it... it was a short question
xD ok lol good luck !
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