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David kicks a soccer ball off the ground and in the air with an initial velocity of 35 feet per second. Using the formula H(t) = -16t2 + vt + s, what is the maximum height the soccer ball reaches? 17.9 feet 18.2 feet 18.7 feet 19.1 feet I believe it is C
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@greenlegodude57
H(t)= -16t2 + vt + s initially s=0 because the ball was in the ground H'(t)=-32t+35 H'(t)=0 t=35/32=1.09375 so H(1.09375)=-16(1.09375)²+35(1.09375)=19.1 so it's D hope it helps:)
oh thank you, I got confused when it had s because i didn't know what it would be
^_^
V = 35 S = 0
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@sidsiddhartha Got it right, usually when it doesn't tell you what 's' is it's almost always a 0.
yeah @greenlegodude57 :)
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