find the set of limit points of
R={ x/x∈R }
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There are no limit points. For any neighborhood of \(x\in R\), you will never find a point that does not lie in \(R\).
can you tell me stepwise,i have to explain the procedure of how it is solved
^ that implies that every point is a limit point, not that there are none.
how to prove it @Jemurray3
What's the definition of a limit point?
@Jemurray3, you're right, I had the definition wrong in my mind.
A point x in X is a limit point of S if every neighbourhood of x contains at least one point of S different from x itself?
Yes. So, written in more precise language, A point \( x \in S\) is a limit point of \(S\) if, for all \( \epsilon > 0\), there exists a point \(y \in S\) such that \( 0 < |x-y| < \epsilon \). So a proof that every point in the set of real numbers is a limit point might begin like this: Let \( \epsilon > 0\) and \(x \in R\) be given. We seek to demonstrate that there exists some \( y \in R\) such that \( 0 <|x-y| < \epsilon \). [...] So your job now is to pick some real number Y that would make that statement true. Don't think too hard - there are an infinite number of choices, and all of them are fairly obvious.
oh thanks ^^,
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