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Mathematics 9 Online
OpenStudy (compassionate):

Geometry question: How would I find the the other end-point and x? http://prntscr.com/3ljc2g

OpenStudy (anonymous):

Use the midpoint formula

OpenStudy (anonymous):

If the other end point has an x-coordinate 'x', then by midpoint formula, the x-coordinate of (18, -1) is average of that of (25, -5), so you get \[ 18 = \frac{x + 25}{2} \]

OpenStudy (anonymous):

Solving which, you get x = 11

OpenStudy (compassionate):

M = (x1 + x1/2), (y1 + y2/1) But isn't the midpoint formula:

OpenStudy (anonymous):

The midpoint formula is \[ (x, y) = \left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} \right)\] and we have used only the x-coordinate part, that is, \[x=\frac{x_1+x_2}{2}\]

OpenStudy (compassionate):

Okay... So we are given (25, -5)(18, -1) So... x = x1 + x2/2 x = 25 + 18/2 That's what I would do, but you did something different. CAn you explain what you did?

OpenStudy (anonymous):

Yes, that's because 'x' is not the x-coordinate of the midpoint, but that of an endpoint, so it actually goes in place of x2

OpenStudy (compassionate):

I'm confused...

OpenStudy (anonymous):

You need to see the arrangement of points One end point: (25, -5) Midpoint (18, -8) Second end point: (x, y) now if you apply the mid point formula, 18 should be the average of 25 and x, that is, \[ 18 = \frac{25 + x}{2} \]

OpenStudy (anonymous):

*sorry it's (18, -1)

OpenStudy (compassionate):

What do you mean the average?

OpenStudy (anonymous):

If you see the midpoint formula, it clearly is a formula for the average of the two end points; It states that the coordinates of the midpoint are the average of those of the end points.

OpenStudy (anonymous):

Don't worry about the 'average', focus more on the position of points. You are solving it with (x, y) as a midpoint instead of (18, -1).

OpenStudy (anonymous):

I could help you if you want my help and you don't runaway from me @Compassionate

OpenStudy (anonymous):

Give you 5mins think about it I will be more than happy if you tag me.

OpenStudy (anonymous):

YES!!!!!!!!! can I help you?

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